Resposta :
V → 200+100+50=350
F → 200-100-50=50
V → 200-100-50= 50 e 4!+26=50
F → 100-(50+50)=0 e 0!=1
V → 100-(50+50)=0
V → (200+100)-300=0 e 0>-2
V → 2×50/1=100 e 100>200
V → 200+100+50=350
F → 200-100-50=50
V → 200-100-50= 50 e 4!+26=50
F → 100-(50+50)=0 e 0!=1
V → 100-(50+50)=0
V → (200+100)-300=0 e 0>-2
V → 2×50/1=100 e 100>200