Resposta :
[tex] > \: resolucao \\ \\ \geqslant \: progressao \: \: geometrica \\ \\ an = 16 \\ q = 2 \\ n = 6 \\ \\ = = = = = = = = = = = = = = \\ \\ > \: o \: primeiro \: termo \: da \: pg \\ \\ an = a1 \times q {}^{n - 1} \\ 16 = a1 \times 2 {}^{6 - 1} \\ 16 = a1 \times 2 {}^{5} \\ 16 = a1 \times 32 \\ a1 = \frac{16}{32} \\ a1 = \frac{1}{2} \\ \\ \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant [/tex]
