[tex] > \: resolucao \\ \\ \geqslant \: area \: \: do \: \: triangulo \\ \\ base = 60cm \\ altura = \frac{2}{5} de60 = \frac{60}{5} \times 2 = 12 \times 2 = 24cm \\ \\ = = = = = = = = = = = = = = = = \\ \\ \\ a = \frac{b \times h}{2} \\ \\ a = \frac{60 \times 24}{2} \\ \\ a = \frac{1440}{2} \\ \\ a = 720cm {}^{2} \\ \\ \\ \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \geqslant \geqslant [/tex]
