Resposta:
x' = 1
x'' = 5
Explicação passo a passo:
[tex]4x^{2} -24x+20=0\\\\\frac{4x^{2} -24x+20}{4} =\frac{0}{4} \\\\x^{2} -6x+5=0[/tex]
[tex]Para\ ax^{2} +bx+c=0:[/tex]
[tex]a=1\ ,\ b=-6\ ,\ c=5[/tex]
[tex]Fo\´rmula\ de\ Bhaskara:[/tex]
[tex]x=\frac{-b\pm\sqrt{b^{2} -4ac} }{2a}\\\\x=\frac{-(-6)\pm\sqrt{(-6)^{2} -4(1)(5)} }{2(1)}\\\\x=\frac{6\pm\sqrt{36 -20} }{2}\\\\x=\frac{6\pm\sqrt{16} }{2}\\\\x=\frac{6\pm\sqrt{4^{2} } }{2}\\\\x=\frac{6\pm4 }{2}\\\\x=3\pm 2[/tex]
[tex]x'=3-2\\\\x'=1\\\\\\x''=3+2\\\\x''=5[/tex]
