Resposta :
[tex] > resolucao \\ \\ \geqslant progressao \: \: geometrica \\ \\ an = a1 \times q {}^{n - 1} \\ \frac{1}{32} = a1 \times ( \frac{1}{4} ) {}^{5 - 1} \\ \frac{1}{32} = a1 \times ( \frac{1}{4} ) {}^{4} \\ \frac{1}{32} = a1 \times \frac{1}{256} \\ a1 = \frac{ \frac{1}{32} }{ \frac{1}{256} } \\ a1 = \frac{1}{32} \times \frac{256}{1} \\ a1 = \frac{256}{32} \\ a1 = 8 \\ \\ \\ \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \geqslant [/tex]
