Determine X:
hip = 20
cat oposto = 10
cat adjacente = x

[tex] \mathsf{x^2+10^2=20^2 }[/tex]
[tex] \mathsf{ x^2+100=400}[/tex]
[tex] \mathsf{ x^2=400-100}[/tex]
[tex] \mathsf{ x^2=300}[/tex]
[tex] \mathsf{ x=\sqrt{300}}[/tex]
[tex] \mathsf{x=\sqrt{2^2\cdot3\cdot5^2} }[/tex]
[tex] \mathsf{ x=2\cdot5\sqrt{3}}[/tex]
[tex]\boxed{\boxed{ \mathsf{ x=10\sqrt{3}}}}[/tex]
Resposta:
Olá boa tarde!
Seja "a" a medida da hipotenusa e "b" e "c" os catetos. Por Pitágoras:
a²= b² + c²
Para:
a = 20 ; b = 10
20² = 10² + c²
c² = 400 - 100
c² = 300
c = [tex]\sqrt{300}[/tex]
c = [tex]\sqrt{100*3}[/tex]
c = [tex]\sqrt{100} *\sqrt{3}[/tex]
c = [tex]10\sqrt{3}[/tex]