Resposta:
361/36
Explicação passo a passo:
[tex]f(x)=3x+\sqrt{10-x}-34\\\\f'(x)= 3 -\frac{1}{2\sqrt{x-10} } -0\\\\f'(x)=0\\\\3-\frac{1}{2\sqrt{x-10} }=0 \\\\\frac{1}{2\sqrt{x-10} }=3\\\\6\sqrt{x-10} =1\\\\36(x-10)=1^2\\\\36x-360=1\\\\36x=361\\\\x=\frac{361}{36}[/tex]
