me ajudem por favor obrigado
[tex]l \sqrt[4]{81} \: \:m \sqrt[ 5]{0} \: \: \: n \sqrt[5]{ - 32} \: \: o \sqrt[6]{64} \: \: \: p \sqrt[7]{ - 1} [/tex]

[tex] \sqrt{49} = \sqrt{7 \times 7} = \sqrt{7 {}^{2} } = 7 \\ \sqrt{100} = \sqrt{10 \times 10} = \sqrt{10 {}^{2} } = 10 \\ \sqrt{0} = 0 \\ \sqrt[3]{8} = \sqrt[3]{2 \times 2 \times 2} = \sqrt[3]{2 {}^{3} } = 2 \\ \sqrt[3]{ - 8} = \sqrt[3]{ - 2 \times - 2 \times - 2} = \sqrt[3]{ - 2 {}^{3} } = - 8 \\ \sqrt[3]{125} = \sqrt[3]{5 \times 5 \times 5} = \sqrt[3]{5 {}^{3} } = 5 \\ \sqrt[3]{ - 1} = - 1 \\ \sqrt[4]{1} = \sqrt[4]{1} = \sqrt[4]{1 \times 1 \times 1 \times 1} = \sqrt[4]{1 {}^{4} } = 1 \\ \sqrt[4]{16} = \sqrt[4]{2 \times 2 \times 2 \times 2} = \sqrt[4]{2 {}^{4} } = 2 \\ \sqrt[3]{ - 1000} = \sqrt[3]{ - 10 \times - 10 \times - 10} = \sqrt[3]{ - 10 {}^{3} } = - 10[/tex]

Franciscosuassuna12go Franciscosuassuna12go · Answer 2

Franciscosuassuna12go Franciscosuassuna12go

Explicação passo-a-passo:

[tex]a) \sqrt{49} = 7[/tex]

[tex]b) \sqrt{100} = 10[/tex]

[tex]c) \sqrt{0} = 0[/tex]

[tex]d) \sqrt[3]{8} = 2[/tex]

[tex]e) \sqrt[3]{ - 8} = - 2[/tex]

[tex]f) \sqrt[3]{125} = 5[/tex]

[tex]g) \sqrt[3]{ - 1} = - 1[/tex]

[tex]h) \sqrt[4]{1} = 1[/tex]

[tex]i) \sqrt[4]{16} = 2[/tex]

[tex]j) \sqrt[3]{ - 1000} = - 10[/tex]

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