Resposta :
x²+y²-4x-6y+3=0
(2a+1)²+(a)²-4(2a+1)-6a +3=0
4a²+4a+1+a²-8a-4-6a+3 =0
5a²-10a = 0
a = 2
ou
a = 0
(2a+1)²+(a)²-4(2a+1)-6a +3=0
4a²+4a+1+a²-8a-4-6a+3 =0
5a²-10a = 0
a = 2
ou
a = 0