x = 8
x' = -4
Explicação passo-a-passo:
[tex]x {}^{2} - 4x - 32 = 0 \\ x = \frac{ - b + - \sqrt{( - b) {}^{2} - 4 \times a \times c } }{2 \times a} \\ \\ x = \frac{ - ( - 4 )+ - \sqrt{ ( - 4) {}^{2} - 4 \times 1 \times ( - 32)} }{2 \times 1} \\ \\ x = \frac{4 + - \sqrt{16 + 128} }{2} \\ \\ x = \frac{4 + - \sqrt{144} }{2} \\ \\ x = \frac{4 + -12 }{2} \\ \\ x = \frac{4 + 12}{2} = \frac{16}{2} = 8 \\ \\ x = \frac{4 - 12}{2} = - \frac{8}{2} = - 4[/tex]
