Resposta:
Explicação passo a passo:
[tex]\frac{2.(x-1)}{3}+\frac{3.(1+x)}{2}=\frac{1}{2}-\frac{x-1}{3}[/tex]
[tex]mmc(2;3)=6[/tex]
[tex]\frac{4.(x-1)}{6} +\frac{9.(1+x)}{6} =\frac{3}{6}-\frac{2.(x-1)}{6}[/tex]
[tex]\frac{4x-4}{6}+\frac{9+9x}{6} =\frac{3}{6}-\frac{2.(x-1)}{6}[/tex]
[tex]\frac{13x+5}{6} =\frac{3-2.(x-1)}{6}[/tex]
[tex]\frac{13x+5}{6} =\frac{3-2x+2}{6}[/tex]
[tex]13x+5=-2x+5[/tex]
[tex]13x+2x=5-5[/tex]
[tex]15x=0[/tex]
[tex]x=0/15[/tex]
[tex]x=0[/tex]
[tex]S=\{0\}[/tex]
