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a)3.x+2.(x+1)+x²=

b)3.(x+y+z)-3.x-3.y-3.z=



Resposta :

Resposta:

a)3.x+2.(x+1)+x²=

[tex]3x + 2x + 2 + {x}^{2} \\ {x}^{2} + 5x + 2[/tex]

b)3.(x+y+z)-3.x-3.y-3.z=

[tex]3x + 3y + 3z - 3x - 3y - 3z \\ = 0[/tex]