Resposta :
[tex]\Delta =b^{2} -4ac=( -6)^{2} -4\cdotp 1\cdotp 9=0 \\ \\ x=\frac{-b\pm \sqrt{\Delta }}{2a} =\frac{6\pm 0}{2\cdotp 1} \Longrightarrow \boxed{x=3} \\ \\ \therefore \boxed{\boxed{S=\{x\in \mathbb{R} |x=3\}}}[/tex]
[tex]\Delta =b^{2} -4ac=( -6)^{2} -4\cdotp 1\cdotp 9=0 \\ \\ x=\frac{-b\pm \sqrt{\Delta }}{2a} =\frac{6\pm 0}{2\cdotp 1} \Longrightarrow \boxed{x=3} \\ \\ \therefore \boxed{\boxed{S=\{x\in \mathbb{R} |x=3\}}}[/tex]