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Resolva a equação
[tex]x {}^{2} - 6x + 9 = 0[/tex]

URGENTEEEEEEEE!!!!!!!!!!!​


Resposta :

[tex]\Delta =b^{2} -4ac=( -6)^{2} -4\cdotp 1\cdotp 9=0 \\ \\ x=\frac{-b\pm \sqrt{\Delta }}{2a} =\frac{6\pm 0}{2\cdotp 1} \Longrightarrow \boxed{x=3} \\ \\ \therefore \boxed{\boxed{S=\{x\in \mathbb{R} |x=3\}}}[/tex]