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Respondido

a) 5x^{2} -x-1=0
b)x^{2} +x+2=0
c)3x^{2} +108=0

Resposta :

Julyassouza5go

Resposta:

a) 5x^{2} -x-1=0

[tex]=1±21√10[/tex]

b)x^{2} +x+2=0

[tex]=−1±−7√2[/tex]

c)3x^{2} +108=0 [tex]32+108=03x^{2}+108=03x2+108=03(2+36)=0[/tex]

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