Resposta:
a) x²-6x+10=0
\begin{gathered}\Delta=(-6)^2-4.1.10=36-40 =-4 \\ \\ x=\frac{6+-\sqrt{-4}}{2}=\frac{6+-2i}{2}=3+-i \\ \\ S=\{3+i,3-i \}\end{gathered}Δ=(−6)2−4.1.10=36−40=−4x=26+−−4=26+−2i=3+−iS={3+i,3−i}
b)-x²+4x-29=0
\begin{gathered}\Delta=4^2-4.(-1)(-29)=16-116=-100 \\ \\ x=\frac{-4+-\sqrt{-100}}{-2}=\frac{-4+-10i}{-2}=2+-5i \\ \\ S=\{2+5i,2-5i \}\end{gathered}Δ=42−4.(−1)(−29)=16−116=−100x=−2−4+−−100=−2−4+−10i=2+−5iS={2+5i,2−5i}
espero ter ajudado!
Mas não sei a (c e nem a d )
