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Luisferreira38go
Respondido

[tex]\lim_{n \to \infty} \frac{x^{2} -1}{x-1}[/tex]

Resposta :

[tex]\lim_{x \to \infty} \frac{x^{2} -1}{x-1} = \lim_{x \to \infty} \frac{(x+1).(x-1)}{x-1}= \lim_{x \to \infty} {x+1} = \infty+1 =\infty[/tex]

Resposta: [tex]\infty[/tex]

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