Resposta :
[tex]\Large\displaystyle\text{$\begin{gathered} \sf{ \tt 90\,km/h \xrightarrow{ \div 3,6}} = 25\,m/s\end{gathered}$}[/tex]
[tex]\Large\displaystyle\text{$\begin{gathered} \sf{ E_c=\dfrac{1}{2}\cdot m\cdot v^2 } \end{gathered}$}[/tex]
[tex]\Large\displaystyle\text{$\begin{gathered} \sf{ E_c=\dfrac{1}{2}\cdot40\cdot25^2} \end{gathered}$}[/tex]
[tex]\Large\displaystyle\text{$\begin{gathered} \sf{ E_c=20\cdot625 } \end{gathered}$}[/tex]
[tex]\Large\displaystyle\text{$\begin{gathered} \boxed{\boxed{\sf{ E_c=12\,500 \,J }}} \end{gathered}$}[/tex]