Resposta:
Logo, a derivada é y'=2. Abraço! bons estudos!!!
[tex]\frac{d}{dx}c=0\\\\\frac{d}{dx}x^n=nx^{n-1}\\\\\\\\\frac{d}{dx}(x+1)(2x-1)\\\\\frac{d}{dx}(2x^2+x-1)\\\\2.2x^{2-1}+x^{1-1}+0\\\\\frac{d}{dx}(f(x))=4x+1[/tex]
