Resposta :
Resposta:
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Resposta:
A.
[tex]\sqrt{16} = 4[/tex]
B.
[tex] \sqrt[3]{ - 27} = \\ - \sqrt[3]{27} \\ - \sqrt[3]{3} {}^{3} \\ - 3
[/tex]
C.
[tex]\sqrt[5]{0} = 0[/tex]
D.
[tex] \sqrt[4]{4096} = 8[/tex]