Resposta:
[tex]\textsf{Leia abaixo}[/tex]
Explicação passo a passo:
[tex]\mathsf{A = Comprimento \times Largura}[/tex]
[tex]\mathsf{204 = x(x + 5)}[/tex]
[tex]\mathsf{x^2 + 5x - 204 = 0}[/tex]
[tex]\mathsf{\Delta = b^2 - 4.a.c}[/tex]
[tex]\mathsf{\Delta = 5^2 - 4.1.(204)}[/tex]
[tex]\mathsf{\Delta = 25 + 816}[/tex]
[tex]\mathsf{\Delta = 841}[/tex]
[tex]\mathsf{x = \dfrac{-b \pm \sqrt{\Delta}}{2a} = \dfrac{-5 \pm \sqrt{841}}{2} \rightarrow \begin{cases}\mathsf{x' = \dfrac{-5 + 29}{2} = \dfrac{24}{2} = 12}\\\\\mathsf{x'' = \dfrac{-5 - 29}{2} = \dfrac{-34}{2} = -17}\end{cases}}[/tex]
[tex]\mathsf{Largura = 12\:m}[/tex]
[tex]\mathsf{Comprimento = 12 + 5 = 17\:m}[/tex]
