[tex]\boxed{\begin{array}{l}\rm A~partir~da~equac_{\!\!,}\tilde ao~balanceada (abaixo),responda\\\rm, verdadeiro~ou~falso~para~a~afirmativa.\\\\\sf Ca_3(PO_4)_2+3H_2SO_4\longrightarrow 2H_3PO_4+3CaSO_4\end{array}}[/tex]
[tex]\boxed{\begin{array}{l}\rm O~n\acute umero~de~mol\acute eculas~de~Ca_3(PO_4)_2\\\rm necess\acute ario~para~a~produc_{\!\!,}\tilde ao~de~6~mols~de~H_3PO_4\\\rm \acute e~3,6\cdot10^1.\\\rm Dados:~Ca=40\,P=31\, S=32\,H=1\, O=16\end{array}}[/tex]
[tex]\large\boxed{\begin{array}{l}\sf 6\cdot10^{23}~mol\acute eculas\longrightarrow 2~mols~de~H_3PO_4\\\sf ~~~~~~~~x~mol\acute eculas\longrightarrow 6~mols~de~H_3PO_4\\\sf 2x=6\cdot6\cdot10^{23}\\\sf x=\dfrac{36\cdot10^{23}}{2}\\\sf x=18\cdot10^{23}=1,8\cdot10^{24}~mol\acute eculas\\\sf portanto~a~afirmativa~\acute e~falsa.\end{array}}[/tex]
