Utilizando l'Hôpital
[tex]\lim_{x \to 0}\frac{\sin2x}{x}\\\\ \lim_{x \to 0} 2.\cos2x=2[/tex]
Sem utilizar l'Hôpital:
[tex]\lim_{x \to 0}\frac{\sin2x}{x}\\\\ \lim_{x \to 0}\frac{2\sin(x).\cos(x)}{x}\\\\2(\lim_{x \to 0}\frac{\sin(x)}{x}.\lim_{x \to 0}\frac{\cos(x)}{x})\\\\2(1.1)=2[/tex]
