Resposta :
[tex]\bar{\theta}_{merc\acute{u}rio}\approx400\ºC\\ \bar{\theta}_{urano}\approx-216\ºC\\\\ \boxed{\Delta \theta=\bar{\theta}_{merc\acute{u}rio}-\bar{\theta}_{urano}}[/tex]
[tex]\Delta \theta\approx400-(-216)\ \therefore[/tex]
[tex]\boxed{\Delta \theta\approx616\ºC}[/tex]