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x²y-xy², para x=1/5 e y=1/2
quero a resolução​


Resposta :

[tex](\frac{1}{5} )^{2} . \frac{1}{2} - (\frac{1}{5} ) . (\frac{1}{2} )^{2} =\\\\\frac{1}{25} .\frac{1}{2} - \frac{1}{5} . \frac{1}{4} =\\\\\frac{1}{50} - \frac{1}{20} =\\\\\frac{2-5}{100} = -\frac{3}{100} = - 0,03[/tex]

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