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Brunno7561go
Respondido

Determine a reta que passa pelo ponto C(4, 3) e possui coeficiente angular igual ⅕. 

x - 5y + 11 = 0

5x - y + 11 = 0

x - 5y + 19 = 0

x + 5y -19 = 0

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Resposta :

Worgingo

[tex]y-y_0=m(x-x_0)\\\\y-3=\frac{1}{5}(x-4)\\\\y=\frac{x}{5}-\frac{4}{5}+3\\\\y=\frac{x}{5}+\frac{11}{5}\\\\5y=x+11\\\\x-5y+11=0[/tex]

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