A)
[tex] \frac{300 - 32}{9} = \frac{tc}{5} [/tex]
Multiplica cruzado
[tex]tc.9 = 268.5[/tex]
[tex]9tc = 1340[/tex]
[tex]tc = 1340 \div 9[/tex]
tc= 148,88°C
B)
[tex] \frac{250}{5} = \frac{tf - 32}{9} [/tex]
[tex](tf - 32).5 = 250.9[/tex]
[tex]5tf - 160 = 2250[/tex]
[tex]5tf = 2250 + 160[/tex]
[tex]tf = 2410 \div 5[/tex]
[tex]tf = 482[/tex]
tf= 482°F
C)
[tex] \frac{150 - 273}{5} = \frac{tc}{5} [/tex]
[tex]tc.5 = - 123.5[/tex]
[tex]tc = - 615 \div 5[/tex]
[tex]tc = - 123c[/tex]
tc= -123°C
Espero ter ajudado!
