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Letymiranda3124go
Respondido


lim
X→4
[tex] \frac{ \sqrt{2( {x} ^{2} - 8) + x} }{x + 4} [/tex]
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Resposta :

Niltonjunior20oss764go

[tex]\lim_{x \to 4} \dfrac{\sqrt{2(x^2-8)+x}}{x+4}=\dfrac{\sqrt{2(4^2-8)+4}}{4+4}=[/tex]

[tex]=\dfrac{\sqrt{20}}{8}=\dfrac{2\sqrt{5}}{8}=\boxed{\dfrac{\sqrt{5}}{4}}[/tex]

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