Resposta :
[tex] {x}^{2} + 3x - 4x - 12 = \\ x(x +3 ) - 4( x+ 3) = \\ (x + 3)(x - 4) = \\ x + 3 = 0 \\ x - 4 = 0 \\ x = - 3 \\ \\ x = 4.[/tex]
s = {-3, 4}
[tex] {x}^{2} + 3x - 4x - 12 = \\ x(x +3 ) - 4( x+ 3) = \\ (x + 3)(x - 4) = \\ x + 3 = 0 \\ x - 4 = 0 \\ x = - 3 \\ \\ x = 4.[/tex]
s = {-3, 4}