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[tex] \frac{x}{3} + \frac{9}{x} = - 2[/tex]

me ajudemm, porfavor!!!!


Resposta :

[tex]\boxed{\begin{array}{l}\sf\dfrac{x}{3}+\dfrac{9}{x}=-2\cdot(3x)\\\sf x^2+27=-6x\\\sf x^2+6x+27=0\\\sf\Delta=b^2-4ac\\\sf\Delta=6^2-4\cdot1\cdot27\\\sf\Delta=36-108\\\sf\Delta=-72<0\\\sf S=\varnothing\end{array}}[/tex]