Resposta :
[tex]\boxed{\begin{array}{l}\sf\dfrac{x}{3}+\dfrac{9}{x}=-2\cdot(3x)\\\sf x^2+27=-6x\\\sf x^2+6x+27=0\\\sf\Delta=b^2-4ac\\\sf\Delta=6^2-4\cdot1\cdot27\\\sf\Delta=36-108\\\sf\Delta=-72<0\\\sf S=\varnothing\end{array}}[/tex]
[tex]\boxed{\begin{array}{l}\sf\dfrac{x}{3}+\dfrac{9}{x}=-2\cdot(3x)\\\sf x^2+27=-6x\\\sf x^2+6x+27=0\\\sf\Delta=b^2-4ac\\\sf\Delta=6^2-4\cdot1\cdot27\\\sf\Delta=36-108\\\sf\Delta=-72<0\\\sf S=\varnothing\end{array}}[/tex]