Resposta:
Explicação:
V0 = 40,3 Km/h => [tex]V_{0} = \frac{40,3}{3,6} = 11,2 m/s[/tex]
Vf = 79,4 Km/h => [tex]V_{f} = \frac{79,4}{3,6} = 22 m/s\\[/tex]
[tex]a = \frac{Vf - V0}{t} = \frac{22 - 11,2}{4,09} = \frac{10,8}{4,09} = 2,64 m/s^{2}[/tex]
V =Vf + a , t = 22 + 2,64 . 5,09 = 22 + 13,44 = 35,44 m/s
v = 35,44 . 3,6 = 127,6 Km/h
