Resposta:
falso
Explicação passo-a-passo:
[tex]\sqrt{\sqrt{a}}=\\\\\left(a^{\frac{1}{2}}\right)^{\frac{1}{2}}=\\\a^{\frac{1}{2}\cdot \frac{1}{2}}=\\\\a^{\frac{1}{2}\cdot \frac{1}{2}}=\\[/tex]
[tex]a^{\frac{1}{2}\cdot \frac{1}{2}}=\\\\a^{\frac{1}{4}}=\\=\sqrt[4]{a}[/tex]
