Resposta:
6
[tex] {2}^{0} + ( { - 2})^{6} \times {4}^{ - 3} - ( { - 2})^{3} - ( { \frac{1}{4} })^{ - 1} = \\ 1 + 64 \times \frac{1}{64} + 8 - 4 = \\ 1 + 1 + 4 = 6[/tex]
