Resposta :
Explicação passo-a-passo:
[tex]\blue {{ _{\heartsuit} } \heartsuit_{\heartsuit} } \: \: \mathsf {OI, TUDO \: \: J\acute{O}IA \: ? \: \:\blue {{ _{\heartsuit} } \heartsuit_{\heartsuit} } }[/tex]
a)
[tex] \sf{ {4x}^{2} + 9 = 12x} \\ \sf{ {4x}^{2} + 9 - 12x = 0 } \\ \boxed{\red{ \sf{ {4x}^{2} - 12x + 9 = 0}}}[/tex]
b)
[tex] \sf{ {x}^{2} = x + 12} \\ \boxed{\red{ \sf{ {x}^{2} - x - 12 = 0}}}[/tex]
c)
[tex] \sf{ {2x}^{2} = - 12x - 18 } \\ \sf{ {2x}^{2} = - 12x - 18 \: \: \: \: \: \div (2) } \\ \sf{ {x}^{2} = - 6x - 9 } \\ \boxed{\red{ \sf{ {x}^{2} + 6x + 9 = 0 }}}[/tex]
d)
[tex] \sf{ {x}^{2} + 9 = 4x} \\ \sf{ {x}^{2} + 9 - 4x = 0} \\ \boxed{\red{ \sf{ {x}^{2} - 4x + 9 = 0 }}}[/tex]
e)
[tex] \sf{ {25x}^{2} = 20x - 4 } \\ \boxed{\red{ \sf{ {25x}^{2} - 20x + 4 = 0 }}}[/tex]
f)
[tex] \sf{2x = 15 - {x}^{2} } \\ \sf{2x - 15 + {x}^{2} = 0 } \\ \boxed{\red{ \sf{ {x}^{2} + 2x - 15 = 0 }}}[/tex]
[tex]\mathcal{ATT : ARMANDO}[/tex]
[tex]\mathfrak{\small03\diagup01\diagup2021} \\ \mathfrak{\small{1} :{26} \: \: pm}[/tex]